Panrock wrote:.....but is a great big Lada heater fan motor..... Steve
Lada?.....Lada?.....'com boy, go down the scrappie and get a part with class, say a Jaguar version....
Joking aside, the size and mass of the motor and what it drives will dictate the values of the components within the PPL loop-filter. But first....
Driving the MOSFET with shown arrangement is fine, they're voltage-input devices when used under these conditions, much like a valve/tube. DC wise there's only the leakage current to consider which will be well under 10nA, = 500 Megohms.
They have far more input capacitance than a 'regular' transistor, but this is swamped by the 100n from the gate to 0V in this circuit. So the device is not the problem here.
Assuming the pulses at pins 3 & 14 of the 4046 are clean and stable (within themselves) we can say that all to the left of pin 13 of the 4046 in the diagram is operating correctly. So the problem is with the handful of passive components remaining around the MOSFET.
I would disconnect the 100k resistor from pin 13 of the 4046 (or pull it out of its socket if used) and apply +4.5V to its free end (two 1k resistors in series from +9V to 0V), and run the motor. The pot should give a range of speed control which includes 750RPM. Make a note of min. and max. RPM (if you dare), and the voltage across the motor for each of these three settings. The RPM can be calculated by measing the frequency of the pulses at pin 14 of the 4046, fitted or not.
What I'm trying to determine here is the approximate DC gain with in the loop-filter, when it comes to the AC gain into the equation comes the mechanical inertia of the moving bits. We'll deal with that later.
This circuit has been optimised for small cassette-type motors with far less inertia and generally appears to 'work' with most of them.
Steve, I'll need those numbers before we can go any further.
Steve A.