Scophony(R) system questions
Posted: Tue Nov 07, 2017 2:26 pm
[moderator...] I'm posting this on behalf of Franck Katco - who I see has also just joined the forum. Welcome, Franck...
To Whom it May Concern:
I found Mr. Yanczer's web site last night and further research determined he deceased 3-16//14.
As the site is being maintained, is there someone to whom I could address my question as to how the Scophony® apparatus achieves either 240 or 441 line mode with a vertical polygon of 12 planes and a horizontal polygon of 20 planes.
Mr. Yanczer states that for the UK 405 line transmission standard , the motor would be at 30,375 rpm; 30,375 rotations/60 seconds= 506.25 rotations per second(for the drive motor).
The data does not state the polygon turn rate for either the vertical or horizontal planes, but I am assuming the motor rpm has loss conversions in the polygon rotation transfer and that the actual rate is in the neighborhood of the declared nominal target standard of 405 UK and 441 US.
Is the vertical frame rate so timed that the horizontal scan area actually yields the 405 line count.
Without the vertical movement, a static frame would logically only receive the vertical polygon 12 frame raster.
What is the distance/time formula to describe the line count output?
Please elucidate.
Thank you.
Franck Kato
The Scophony® data by the Wikipedia path has a 23 page 1938 booklet referencing split optics and data storage in the sonic Jeffree Cell.
What is the device doing to provide the horizontal line count and the stated vertical frame rate.
The description of the Jeffree Cell apparently is amplitude modulation of the optic wave fronts to derive a 200 fold increase in light output, thus permitting acceptable theatre pictorial quality.
Mr. Yanczer's 1987 volume, THE MECHANICS OF TELEVISION refers only to the Nipkow disc method rather than the Scophony® system which derives from Czarist Russia's Boris Rosing 1907 per Wikipedia link.
To Whom it May Concern:
I found Mr. Yanczer's web site last night and further research determined he deceased 3-16//14.
As the site is being maintained, is there someone to whom I could address my question as to how the Scophony® apparatus achieves either 240 or 441 line mode with a vertical polygon of 12 planes and a horizontal polygon of 20 planes.
Mr. Yanczer states that for the UK 405 line transmission standard , the motor would be at 30,375 rpm; 30,375 rotations/60 seconds= 506.25 rotations per second(for the drive motor).
The data does not state the polygon turn rate for either the vertical or horizontal planes, but I am assuming the motor rpm has loss conversions in the polygon rotation transfer and that the actual rate is in the neighborhood of the declared nominal target standard of 405 UK and 441 US.
Is the vertical frame rate so timed that the horizontal scan area actually yields the 405 line count.
Without the vertical movement, a static frame would logically only receive the vertical polygon 12 frame raster.
What is the distance/time formula to describe the line count output?
Please elucidate.
Thank you.
Franck Kato
The Scophony® data by the Wikipedia path has a 23 page 1938 booklet referencing split optics and data storage in the sonic Jeffree Cell.
What is the device doing to provide the horizontal line count and the stated vertical frame rate.
The description of the Jeffree Cell apparently is amplitude modulation of the optic wave fronts to derive a 200 fold increase in light output, thus permitting acceptable theatre pictorial quality.
Mr. Yanczer's 1987 volume, THE MECHANICS OF TELEVISION refers only to the Nipkow disc method rather than the Scophony® system which derives from Czarist Russia's Boris Rosing 1907 per Wikipedia link.